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Message-ID: <CAKHv7pj0zVDkd1DvoRU80axPZ-dF+yjxZqRNaHeQyo3jekAn2w@mail.gmail.com>
Date: Mon, 21 Oct 2013 21:59:16 +0200
From: Paul Schutte <sjpschutte@...il.com>
To: musl@...ts.openwall.com
Subject: Re: Re: inet_pton
Hi,
I have tested the suggested fix and this is the result:
: 1 <--
:: 1
::: 0
192.168.1.1 0
:192.168.1.1 1 <--
::192.168.1.1 1
:ffff:192.168.1.1 1 <--
::ffff:192.168.1.1 1
.192.168.1.1 0
:.192.168.1.1 0
ffff:c0a8:5e4 0
:ffff:c0a8:5e4 1 <--
0:0:0:0:0:ffff:c0a8:5e4 1
0:0:0:0:ffff:c0a8:5e4 0
0::ffff:c0a8:5e4 1
::0::ffff:c0a8:5e4 0
c0a8 0
Those marked with the <-- are still incorrect.
Regards
Paul
On Mon, Oct 21, 2013 at 4:08 AM, Rich Felker <dalias@...ifal.cx> wrote:
> It's not an annoyance at all, and your test cases may be useful for
> writing a regression test, so I'm replying on-list. As you may have
> noticed, I already fixed the first issue you reported, but the second
> issue does remain. nsz has proposed a simple fix: at line 61,
>
> - if (s[j]!='.') return 0;
> + if (s[j]!='.' || brk<0) return 0;
>
> I have not checked this yet but I suspect it's correct. Please let me
> know if it works for you.
>
> Rich
>
>
> On Sun, Oct 20, 2013 at 09:35:32PM +0200, Paul Schutte wrote:
> > Hi Rich,
> >
> > I send this directly to you as I think I am starting to annoy the people
> on
> > the list with this.
> >
> > I have done some testing on this and here is the result:
> >
> >
> >
> > proper
> > before : 0
> > 1 :: 1
> > 1 ::: 0
> > 0 192.168.1.1 0
> > 1 :192.168.1.1 0
> > 1 ::192.168.1.1 1
> > 1 :ffff:192.168.1.1 0
> > 1 ::ffff:192.168.1.1 1
> > 1 .192.168.1.1 0
> > 0 :.192.168.1.1 0
> > 0 ffff:c0a8:5e4 0
> > 0 :ffff:c0a8:5e4 0
> > 1 0:0:0:0:0:ffff:c0a8:5e4 1
> > 1 0:0:0:0:ffff:c0a8:5e4 0
> > 0 0::ffff:c0a8:5e4 1
> > 1 ::0::ffff:c0a8:5e4 0
> > 0 c0a8 0
> > 0
> > The following seems to produce the correct output:
> >
> > --- a/musl/src/network/inet_pton.c
> > +++ b/musl/src/network/inet_pton.c
> > @@ -14,11 +14,11 @@
> > return -1;
> > }
> >
> > -int inet_pton(int af, const char *restrict s, void *restrict a0)
> > +int inet_pton(int af, const char *restrict s0, void *restrict a0)
> > {
> > uint16_t ip[8];
> > unsigned char *a = a0;
> > - const char *z;
> > + const char *z, *s = s0;
> > unsigned long x;
> > int i, j, v, d, brk=-1, need_v4=0;
> >
> > @@ -36,7 +36,13 @@
> > return -1;
> > }
> >
> > - if (s[0]==':' && s[1]==':') s++;
> > + if (s[0]==':') {
> > + if (s[1]==':') {
> > + s++;
> > + } else {
> > + return 0;
> > + }
> > + }
> >
> > for (i=0; ; i++, s+=j+1) {
> > if (s[0]==':' && brk<0) {
> > @@ -73,6 +79,9 @@
> > *a++ = ip[j]>>8;
> > *a++ = ip[j];
> > }
> > +
> > + if (s==s0) return 0;
> > +
> > if (need_v4 && inet_pton(AF_INET, (void *)s, a-4) <= 0) return 0;
> > return 1;
> > }
> >
> >
> > I used the following to test:
> >
> > #include <ctype.h>
> > #include <netdb.h>
> > #include <stdarg.h>
> > #include <stdio.h>
> > #include <stdlib.h>
> > #include <string.h>
> > #include <sys/socket.h>
> > #include <sys/un.h>
> > #include <netinet/in.h>
> > #include <arpa/inet.h>
> >
> > void test(char *s) {
> > char buf[256];
> > int musl;
> > musl=inet_pton(AF_INET6, s, (void*)buf);
> > printf("%s=%d\n",s,musl);
> > }
> >
> > int main() {
> >
> > test(":");
> > test("::");
> > test(":::");
> > test("192.168.1.1");
> > test(":192.168.1.1");
> > test("::192.168.1.1");
> > test(":ffff:192.168.1.1");
> > test("::ffff:192.168.1.1");
> > test(".192.168.1.1");
> > test(":.192.168.1.1");
> > test("ffff:c0a8:5e4");
> > test(":ffff:c0a8:5e4");
> > test("0:0:0:0:0:ffff:c0a8:5e4");
> > test("0:0:0:0:ffff:c0a8:5e4");
> > test("0::ffff:c0a8:5e4");
> > test("::0::ffff:c0a8:5e4");
> > test("c0a8");
> >
> > return 0;
> > }
> >
> > The output is as follows which seems to be the desired outcome:
> > :=0
> > ::=1
> > :::=0
> > 192.168.1.1=0
> > :192.168.1.1=0
> > ::192.168.1.1=1
> > :ffff:192.168.1.1=0
> > ::ffff:192.168.1.1=1
> > ..192.168.1.1=0
> > :.192.168.1.1=0
> > ffff:c0a8:5e4=0
> > :ffff:c0a8:5e4=0
> > 0:0:0:0:0:ffff:c0a8:5e4=1
> > 0:0:0:0:ffff:c0a8:5e4=0
> > 0::ffff:c0a8:5e4=1
> > ::0::ffff:c0a8:5e4=0
> > c0a8=0
> >
> >
> > Hope I you find this use full.
> >
> > Regards
> > Paul
>
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