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Message-ID: <CAFdMc-1+HwmxTpxDmYkc+5s9YeYtp0WSO980vvZSurAzKO+92A@mail.gmail.com>
Date: Tue, 10 Apr 2018 18:27:24 -0300
From: "dgutson ." <danielgutson@...il.com>
To: musl@...ts.openwall.com
Subject: Re: catan errors
On Tue, Apr 10, 2018 at 5:50 PM, Rich Felker <dalias@...c.org> wrote:
> On Tue, Apr 10, 2018 at 05:41:46PM -0300, dgutson . wrote:
> > On Tue, Apr 10, 2018 at 5:32 PM, Rich Felker <dalias@...c.org> wrote:
> >
> > > On Tue, Apr 10, 2018 at 05:23:12PM -0300, dgutson . wrote:
> > > > On Tue, Apr 10, 2018 at 4:50 PM, Rich Felker <dalias@...c.org>
> wrote:
> > > >
> > > > > The OpenBSD catan implementation we're using has a number of
> > > > > nonsensical "overflow" (goto ovrf) conditions that aren't errors,
> > > > > reported by mepholic on irc. I think the attached patch fixes them
> > > > > without introducing new problems, but I'm not sure if any other
> > > > > problems remain.
> > > > >
> > > > > Note that, of the three cases removed:
> > > > >
> > > > > 1. Is not an exceptional case at all, and made no sense to begin
> with..
> > > > >
> > > > > 2. Is only exceptional if x and a are both zero; atan(2x,0) is
> > > > > perfectly well-defined.
> > > > >
> > > > > 3. Is only possible if y==1.0 and x==0.0, which is the only real
> > > > > exceptional case for atan: z==I.
> > > > >
> > > >
> > > >
> > > > Besides the trigonometric case, are you considering de-normalized
> > > numbers,
> > > > such as 4.94066e-324 as divisor?
> > > > For example:
> > > > double x = 1.0;
> > > > double y = 5E-324;
> > > > x / y is inf, and y != 0.0.
> > > > Shouldn't 'a' be checked against that number or its absolute value >=
> > > > minimum?
> > >
> > > Can you clarify where you think something goes wrong?
> > >
> >
> > - if (a == 0.0)
> > - goto ovrf;
> >
> > t = y + 1.0;
> > a = (x2 + t * t)/a;
> >
> >
> > The check you removed does not look correct for me because what I
> mentioned..
> > However, shouldn't you check, before the division, that a is not the
> > nearest to zero (+ or -) denormalized representable double,
> > in order to avoid ending in inf?
>
> Here a=x²+(y-1)², so unless both x==0 and y==1, the smallest a can be
>
I was worried by the case when x is 0 and y is the next (or previous)
representable value nearest to 1.0; the y == 1.0 check will fail, but the
division may get big; so I did a small program and verified that the result
of the division is about 3.24519e+32 when going towards negative and
8.11296e+31 when going towards positive, so everything is OK (I didn't dig
in the atan2 arguments though).
> is DBL_EPSILON². When a is small, the numerator in the last line is
> also small (x²+(1+y)² < 2) so dividing by a does not overflow.
>
> Rich
>
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