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Message-ID: <5f4239740903250752w2679cfbp2d1ad849bf138126@mail.gmail.com>
Date: Wed, 25 Mar 2009 09:52:53 -0500
From: Minga Minga <mingakore@...il.com>
To: john-users@...ts.openwall.com
Subject: Adding Characters to the end of strings inside of DumbForce?
I am using a 'DumbForce' section of john.conf to brute force ALL possible 6
character passwords, But I want to ADD the string '2008' to the end of each
password generated.
(I want it to try aaaaaa2008 aaaaab2008 aaaaac2008 ... ... ..)
Is there a way to do this in john.conf?
Currently I am doing:
./john -external:DumbForce-AllChars -stdout | sed -e 's/$/2008/g' | ./john
-stdin passwd.txt
Which is very wasteful...
Thanks
-Minga
-----
Here is what "DumbForce-AllChars" looks like (the part that matters)
[List.External:DumbForce-AllChars]
int maxlength; // Maximum password length to try
int last; // Last character position, zero-based
int lastid; // Character index in the last position
int id[0x7f]; // Current character indices for other positions
int charset[0x100], c0; // Character set
void init()
{
int minlength;
int i, c;
minlength = 6; // Initial password length to try, must be at least
1
maxlength = 6; // Must be at least same as minlength
i = 0;
charset[i++] = 65;
c = ' ';
while (c < '~')
charset[i++] = c++;
c = '~' + 1;
while (c <= 0x7e)
charset[i++] = c++;
c++;
...
etc
...
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